Optimal. Leaf size=433 \[ \frac{2 \sqrt{-b} d \sqrt{x} \sqrt{\frac{c x}{b}+1} \sqrt{\frac{e x}{d}+1} (c d-b e) \left (7 A c e (2 c d-b e)-B \left (-4 b^2 e^2-b c d e+8 c^2 d^2\right )\right ) \text{EllipticF}\left (\sin ^{-1}\left (\frac{\sqrt{c} \sqrt{x}}{\sqrt{-b}}\right ),\frac{b e}{c d}\right )}{105 c^{5/2} e^3 \sqrt{b x+c x^2} \sqrt{d+e x}}+\frac{2 \sqrt{b x+c x^2} \sqrt{d+e x} \left (3 c e x (7 A c e-4 b B e+B c d)+7 A c e (b e+c d)-B \left (4 b^2 e^2-2 b c d e+4 c^2 d^2\right )\right )}{105 c^2 e^2}+\frac{2 \sqrt{-b} \sqrt{x} \sqrt{\frac{c x}{b}+1} \sqrt{d+e x} \left (\left (-2 b^2 e^2-3 b c d e+8 c^2 d^2\right ) (7 A c e-4 b B e+B c d)+5 c d e (3 b B-7 A c) (2 c d-b e)\right ) E\left (\sin ^{-1}\left (\frac{\sqrt{c} \sqrt{x}}{\sqrt{-b}}\right )|\frac{b e}{c d}\right )}{105 c^{5/2} e^3 \sqrt{b x+c x^2} \sqrt{\frac{e x}{d}+1}}+\frac{2 B \left (b x+c x^2\right )^{3/2} \sqrt{d+e x}}{7 c} \]
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Rubi [A] time = 0.604068, antiderivative size = 433, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 8, integrand size = 28, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.286, Rules used = {832, 814, 843, 715, 112, 110, 117, 116} \[ \frac{2 \sqrt{b x+c x^2} \sqrt{d+e x} \left (3 c e x (7 A c e-4 b B e+B c d)+7 A c e (b e+c d)-B \left (4 b^2 e^2-2 b c d e+4 c^2 d^2\right )\right )}{105 c^2 e^2}+\frac{2 \sqrt{-b} d \sqrt{x} \sqrt{\frac{c x}{b}+1} \sqrt{\frac{e x}{d}+1} (c d-b e) \left (7 A c e (2 c d-b e)-B \left (-4 b^2 e^2-b c d e+8 c^2 d^2\right )\right ) F\left (\sin ^{-1}\left (\frac{\sqrt{c} \sqrt{x}}{\sqrt{-b}}\right )|\frac{b e}{c d}\right )}{105 c^{5/2} e^3 \sqrt{b x+c x^2} \sqrt{d+e x}}+\frac{2 \sqrt{-b} \sqrt{x} \sqrt{\frac{c x}{b}+1} \sqrt{d+e x} \left (\left (-2 b^2 e^2-3 b c d e+8 c^2 d^2\right ) (7 A c e-4 b B e+B c d)+5 c d e (3 b B-7 A c) (2 c d-b e)\right ) E\left (\sin ^{-1}\left (\frac{\sqrt{c} \sqrt{x}}{\sqrt{-b}}\right )|\frac{b e}{c d}\right )}{105 c^{5/2} e^3 \sqrt{b x+c x^2} \sqrt{\frac{e x}{d}+1}}+\frac{2 B \left (b x+c x^2\right )^{3/2} \sqrt{d+e x}}{7 c} \]
Antiderivative was successfully verified.
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Rule 832
Rule 814
Rule 843
Rule 715
Rule 112
Rule 110
Rule 117
Rule 116
Rubi steps
\begin{align*} \int (A+B x) \sqrt{d+e x} \sqrt{b x+c x^2} \, dx &=\frac{2 B \sqrt{d+e x} \left (b x+c x^2\right )^{3/2}}{7 c}+\frac{2 \int \frac{\left (-\frac{1}{2} (3 b B-7 A c) d+\frac{1}{2} (B c d-4 b B e+7 A c e) x\right ) \sqrt{b x+c x^2}}{\sqrt{d+e x}} \, dx}{7 c}\\ &=\frac{2 \sqrt{d+e x} \left (7 A c e (c d+b e)-B \left (4 c^2 d^2-2 b c d e+4 b^2 e^2\right )+3 c e (B c d-4 b B e+7 A c e) x\right ) \sqrt{b x+c x^2}}{105 c^2 e^2}+\frac{2 B \sqrt{d+e x} \left (b x+c x^2\right )^{3/2}}{7 c}-\frac{4 \int \frac{\frac{1}{4} b d \left (7 A c e (c d+b e)-B \left (4 c^2 d^2-2 b c d e+4 b^2 e^2\right )\right )-\frac{1}{4} \left (5 c (3 b B-7 A c) d e (2 c d-b e)+2 (B c d-4 b B e+7 A c e) \left (4 c^2 d^2-\frac{3}{2} b c d e-b^2 e^2\right )\right ) x}{\sqrt{d+e x} \sqrt{b x+c x^2}} \, dx}{105 c^2 e^2}\\ &=\frac{2 \sqrt{d+e x} \left (7 A c e (c d+b e)-B \left (4 c^2 d^2-2 b c d e+4 b^2 e^2\right )+3 c e (B c d-4 b B e+7 A c e) x\right ) \sqrt{b x+c x^2}}{105 c^2 e^2}+\frac{2 B \sqrt{d+e x} \left (b x+c x^2\right )^{3/2}}{7 c}+\frac{\left (d (c d-b e) \left (7 A c e (2 c d-b e)-B \left (8 c^2 d^2-b c d e-4 b^2 e^2\right )\right )\right ) \int \frac{1}{\sqrt{d+e x} \sqrt{b x+c x^2}} \, dx}{105 c^2 e^3}+\frac{\left (5 c (3 b B-7 A c) d e (2 c d-b e)+(B c d-4 b B e+7 A c e) \left (8 c^2 d^2-3 b c d e-2 b^2 e^2\right )\right ) \int \frac{\sqrt{d+e x}}{\sqrt{b x+c x^2}} \, dx}{105 c^2 e^3}\\ &=\frac{2 \sqrt{d+e x} \left (7 A c e (c d+b e)-B \left (4 c^2 d^2-2 b c d e+4 b^2 e^2\right )+3 c e (B c d-4 b B e+7 A c e) x\right ) \sqrt{b x+c x^2}}{105 c^2 e^2}+\frac{2 B \sqrt{d+e x} \left (b x+c x^2\right )^{3/2}}{7 c}+\frac{\left (d (c d-b e) \left (7 A c e (2 c d-b e)-B \left (8 c^2 d^2-b c d e-4 b^2 e^2\right )\right ) \sqrt{x} \sqrt{b+c x}\right ) \int \frac{1}{\sqrt{x} \sqrt{b+c x} \sqrt{d+e x}} \, dx}{105 c^2 e^3 \sqrt{b x+c x^2}}+\frac{\left (\left (5 c (3 b B-7 A c) d e (2 c d-b e)+(B c d-4 b B e+7 A c e) \left (8 c^2 d^2-3 b c d e-2 b^2 e^2\right )\right ) \sqrt{x} \sqrt{b+c x}\right ) \int \frac{\sqrt{d+e x}}{\sqrt{x} \sqrt{b+c x}} \, dx}{105 c^2 e^3 \sqrt{b x+c x^2}}\\ &=\frac{2 \sqrt{d+e x} \left (7 A c e (c d+b e)-B \left (4 c^2 d^2-2 b c d e+4 b^2 e^2\right )+3 c e (B c d-4 b B e+7 A c e) x\right ) \sqrt{b x+c x^2}}{105 c^2 e^2}+\frac{2 B \sqrt{d+e x} \left (b x+c x^2\right )^{3/2}}{7 c}+\frac{\left (\left (5 c (3 b B-7 A c) d e (2 c d-b e)+(B c d-4 b B e+7 A c e) \left (8 c^2 d^2-3 b c d e-2 b^2 e^2\right )\right ) \sqrt{x} \sqrt{1+\frac{c x}{b}} \sqrt{d+e x}\right ) \int \frac{\sqrt{1+\frac{e x}{d}}}{\sqrt{x} \sqrt{1+\frac{c x}{b}}} \, dx}{105 c^2 e^3 \sqrt{1+\frac{e x}{d}} \sqrt{b x+c x^2}}+\frac{\left (d (c d-b e) \left (7 A c e (2 c d-b e)-B \left (8 c^2 d^2-b c d e-4 b^2 e^2\right )\right ) \sqrt{x} \sqrt{1+\frac{c x}{b}} \sqrt{1+\frac{e x}{d}}\right ) \int \frac{1}{\sqrt{x} \sqrt{1+\frac{c x}{b}} \sqrt{1+\frac{e x}{d}}} \, dx}{105 c^2 e^3 \sqrt{d+e x} \sqrt{b x+c x^2}}\\ &=\frac{2 \sqrt{d+e x} \left (7 A c e (c d+b e)-B \left (4 c^2 d^2-2 b c d e+4 b^2 e^2\right )+3 c e (B c d-4 b B e+7 A c e) x\right ) \sqrt{b x+c x^2}}{105 c^2 e^2}+\frac{2 B \sqrt{d+e x} \left (b x+c x^2\right )^{3/2}}{7 c}+\frac{2 \sqrt{-b} \left (5 c (3 b B-7 A c) d e (2 c d-b e)+(B c d-4 b B e+7 A c e) \left (8 c^2 d^2-3 b c d e-2 b^2 e^2\right )\right ) \sqrt{x} \sqrt{1+\frac{c x}{b}} \sqrt{d+e x} E\left (\sin ^{-1}\left (\frac{\sqrt{c} \sqrt{x}}{\sqrt{-b}}\right )|\frac{b e}{c d}\right )}{105 c^{5/2} e^3 \sqrt{1+\frac{e x}{d}} \sqrt{b x+c x^2}}+\frac{2 \sqrt{-b} d (c d-b e) \left (7 A c e (2 c d-b e)-B \left (8 c^2 d^2-b c d e-4 b^2 e^2\right )\right ) \sqrt{x} \sqrt{1+\frac{c x}{b}} \sqrt{1+\frac{e x}{d}} F\left (\sin ^{-1}\left (\frac{\sqrt{c} \sqrt{x}}{\sqrt{-b}}\right )|\frac{b e}{c d}\right )}{105 c^{5/2} e^3 \sqrt{d+e x} \sqrt{b x+c x^2}}\\ \end{align*}
Mathematica [C] time = 3.3896, size = 461, normalized size = 1.06 \[ -\frac{2 \left (b e x (b+c x) (d+e x) \left (B \left (4 b^2 e^2-b c e (2 d+3 e x)+c^2 \left (4 d^2-3 d e x-15 e^2 x^2\right )\right )-7 A c e (b e+c (d+3 e x))\right )+\sqrt{\frac{b}{c}} \left (-i b e x^{3/2} \sqrt{\frac{b}{c x}+1} \sqrt{\frac{d}{e x}+1} (c d-b e) \left (7 A c e (c d-2 b e)-B \left (-8 b^2 e^2+b c d e+4 c^2 d^2\right )\right ) \text{EllipticF}\left (i \sinh ^{-1}\left (\frac{\sqrt{\frac{b}{c}}}{\sqrt{x}}\right ),\frac{c d}{b e}\right )+i b e x^{3/2} \sqrt{\frac{b}{c x}+1} \sqrt{\frac{d}{e x}+1} \left (14 A c e \left (b^2 e^2-b c d e+c^2 d^2\right )+B \left (5 b^2 c d e^2-8 b^3 e^3+5 b c^2 d^2 e-8 c^3 d^3\right )\right ) E\left (i \sinh ^{-1}\left (\frac{\sqrt{\frac{b}{c}}}{\sqrt{x}}\right )|\frac{c d}{b e}\right )+\sqrt{\frac{b}{c}} (b+c x) (d+e x) \left (14 A c e \left (b^2 e^2-b c d e+c^2 d^2\right )+B \left (5 b^2 c d e^2-8 b^3 e^3+5 b c^2 d^2 e-8 c^3 d^3\right )\right )\right )\right )}{105 b c^2 e^3 \sqrt{x (b+c x)} \sqrt{d+e x}} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.059, size = 1526, normalized size = 3.5 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{c x^{2} + b x}{\left (B x + A\right )} \sqrt{e x + d}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\sqrt{c x^{2} + b x}{\left (B x + A\right )} \sqrt{e x + d}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{x \left (b + c x\right )} \left (A + B x\right ) \sqrt{d + e x}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{c x^{2} + b x}{\left (B x + A\right )} \sqrt{e x + d}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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